- #1

- 2

- 0

## Homework Statement

Find the tension in each string given the diagram.

## Homework Equations

Fx = ma.

Fy = ma.

## The Attempt at a Solution

Fy = 0. Because it's at equilibrium.

T1(sin30) + T2(sin60) - mg = 0.

T1 = [mg - T2(sin60)]/(sin30)

Fx = 0.

T1(cos30) + T2(cos60) = 0.

T1 = [-T2(cos60)]/(cos30)

T1 = T1

[mg - T2(sin60)]/(sin30) = [-T2(cos60)]/(cos30)

150/(sin30) = -T2[(cos60)/(cos30)] + T2[(sin60)/(sin30)]

150/(sin30) = T2[[(sin60)/(sin30)] - [(cos60)/(cos30)]]

T2 = 259.8 N

Substitute T2 into

T1 = [-T2(cos60)]/(cos30)

T1 = 150 N.

Therefore,

T1 = 150 N.

T2 = 259.8 N

Is this the right answer?